The component of the external magnetic field along the central axis of a 50 turn circular coil of radius 40.0 cm decreases from 2.90 T to 0.550 T in 3.00 s. The resistance of the coil is R = 4.50 $\Omega$. What is the magnitude I of the current induced in the coil? I = 0.01427 A Incorrect Answer What is the direction of the current if the axial component of the field points away from the viewer? clockwise counter-clockwise Correct Answer
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The radius of the coil is given as $r = 40.0 \, \text{cm} = 0.40 \, \text{m}$. The area of the coil is $A = \pi r^2 = \pi (0.40 \, \text{m})^2 = \pi (0.16) \, \text{m}^2 \approx 0.50265 \, \text{m}^2$. Show more…
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