The compound rx3 decomposes according to the equation 3rx r...

The compound RX3 decomposes according to the equation: 3RX --> R + R2X3 + 3X2. 1. Write the proper expression for the rate of decomposition for RX3, and the rate of formation for R, R2X3, and X2. 2. How is the rate of decomposition of RX3 related to the rate of formation in R2X3? 3. If the rate for the formation of R is 7.5 M/min, what is the rate of decomposition of RX3? 4. What is the rate of the overall reaction? Explain. 5. Given the equation, do you think calculating a value for the rate of the reaction should vary if the reactant is decomposing twice as fast as the formation of the product? Explain.

Transcript

00:01 Hello students in this question the decomposition of rx3 is given.

00:07 We have to answer certain questions asked based on this equation.

00:12 The first one is we have to write the equation for the rate of decomposition of rx3 as there is a decrease in the number of moles of rx3, therefore minus d into concentration of rx3 with a decrease in the number of moles of rx3, therefore minus d into concentration of rx3 with a decrease in the number of more of rx3, time that is d t as there is a three modes we can denote it by one by three the next one is the rate of formation of r as the concentration of the r increases it can be denoted as d r divided by d t and the rate of formation of r two x3 which is similar to the rate of formation of r that is d into concentration of r2 x3 divided by d t and for this 3 x2 molecule d into concentration of h2 divided by d t as there are three molecules it can be represented as 1 by 3 the fifth question is we need to write the overall rate equation the overall rate equation can be written as follows 1 by 3 that is minus 1 1 by 3 d into concentration of r x 3 divided by d t is equal to d concentration of r divided by d t which is equal to d into concentration of r 2 x 3 divided by d t which is equal to 1 by 3 d t which is equal to 1 by 3 d into concentration of x 2 divided by d t this is the overall rate equation.

01:59 In the 6th question, the rate of formation of r is given.

02:03 We need to find out the rate of decomposition of rx3.

02:08 We know that minus 1 by 3 d into concentration of rx3 by d t is equal to d into concentration of r divided by d t.

02:22 Substituting the value we get minus 1 by 3 d t.

02:28 Concentration of rx3 divided by dt is equal to 7 .5...

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