00:01
So this problem tells us that in the year 1990, the average tuition and fees at a private college were about $8 ,050 a year.
00:08
Since then, the annual cost has increased by about $90 per year.
00:13
And our first objective is to write a linear equation in slope intercept form that models the cost, which will represent by the variable c, to attend a private college t years after 1990.
00:25
So the first thing i notice is they mention slope intercept form.
00:29
Now normally when we talk about slope intercept form, we think about y equals mx plus b, where m represents our slope, b represents our y intercept, x is our independent variable, and y is our dependent variable.
00:44
So x and y are quantities that can change.
00:47
Slope is going to be our constant rate of change, and our y intercept is going to be our initial amount or our starting amount, because that's the amount when x equals zero.
00:57
Now in this case we're being asked to not use the variables x and y, but to use the variables c and t.
01:04
So in order to make sure i put those in the right place, like should i put c in the place of y or should i put t? so cost or time, what i like to do is i like to use this sentence, y depends on x because y is always my dependent variable and x is always my independent variable.
01:20
And in this case cost, which is c, depends on time.
01:27
So because of this, what i can see is that the variable y is going to be substituted with c and the variable x is going to be substituted with t.
01:36
So instead of y equals mx plus b, the equation is going to look like c equals mt plus b.
01:45
So m is still going to represent our slope or our constant rate of change.
01:49
B is still going to represent our initial amount.
01:50
Or in this case our c intercept.
01:53
But instead of talking in terms of x and y, we're talking in terms of c and t.
01:57
So i want to look through and see if, do i know my slope? do i know my constant rate of change? and i do.
02:03
It's saying that the annual cost is increasing by about $900 per year...