00:01
There is a normal distribution question.
00:02
So the mean value was given here.
00:04
Let me take notes.
00:05
The mean, which is denoted by mut, this is $3 ,450.
00:10
And the standard division, so the standard division, which is denoted by sigma, that was given as $995.
00:19
And the sample was given here, which is given as 37.
00:23
So what we're going to, so we're going to find the sampling distribution of the sample mean for this one.
00:28
So the sampling for the sampling distribution.
00:32
So the sample, so this is for part a, the sample mean is equal to which is the population mean, and which is equal to the mu, this is 34 and 50, and the sample standard division.
00:48
So for sample standard division, we're going to use the central limit theorem that says the standard division of the population divided by square of the sample size which is 995 divided by which is the square of 37 which would be this is 995 divided by which is the square root of this is square root of 37 so that would be 163 .57 so this is 163 .577 so i can define the random variable x bar which is normal of the so the mean is 3450 and the standard division 163 .57.
01:32
This is the answer we have for the first part of the question.
01:36
Find the probability that the mean credit card balance for the sample for 30 is more than.
01:43
So the probability of getting x bar, which is greater than 3100.
01:47
So i'm going to use the graphic display calculator application, which is normal cdf...