Question

The cross section of a steel beam is constructed of a $\mathrm{W} 18 \times 71$ wide-flange section with a 6 in. $\times 1 / 2$ in. cover plate welded to the top flange and a $C 10 \times 30$ channel section welded to the bottom flange. This beam is subjected to a bending moment $M$ having its vector at an angle $\theta$ to the $z$ axis (see figure). Determine the orientation of the neutral axis and calculate the maximum tensile stress $\sigma_{\mathrm{t}}$ and maximum compressive stress $\sigma_{\mathrm{c}}$ in the beam. Assume that $\theta=30^{\circ}$ and $M=75$ kip-in. Note: The cross-sectional properties of this beam were computed in Examples D-2 and D-5.

          The cross section of a steel beam is constructed of a $\mathrm{W} 18 \times 71$ wide-flange section with a 6 in. $\times 1 / 2$ in. cover plate welded to the top flange and a $C 10 \times 30$ channel section welded to the bottom flange. This beam is subjected to a bending moment $M$ having its vector at an angle $\theta$ to the $z$ axis (see figure).
Determine the orientation of the neutral axis and calculate the maximum tensile stress $\sigma_{\mathrm{t}}$ and maximum compressive stress $\sigma_{\mathrm{c}}$ in the beam. Assume that $\theta=30^{\circ}$ and $M=75$ kip-in. Note: The cross-sectional properties of this beam were computed in Examples D-2 and D-5.
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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The cross section of a steel beam is constructed of a $\mathrm{W} 18 \times 71$ wide-flange section with a 6 in. $\times 1 / 2$ in. cover plate welded to the top flange and a $C 10 \times 30$ channel section welded to the bottom flange. This beam is subjected to a bending moment $M$ having its vector at an angle $\theta$ to the $z$ axis (see figure). Determine the orientation of the neutral axis and calculate the maximum tensile stress $\sigma_{\mathrm{t}}$ and maximum compressive stress $\sigma_{\mathrm{c}}$ in the beam. Assume that $\theta=30^{\circ}$ and $M=75$ kip-in. Note: The cross-sectional properties of this beam were computed in Examples D-2 and D-5.
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Transcript

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00:02 Hey everyone.
00:03 So for this one, we need to get the channel.
00:07 For this part, we have y1 is equals to the depth.
00:14 Def 1 section over 2 plus the depth of plate divided by 2.
00:26 So we have equal to 18 .5 divided by 2 plus 0 .5 divided by 2.
00:30 You have equal to 18 .5 divided by 2 plus 0 .5 divided by 2.
00:33 You have equal to 9 .25 plus 0 .25.
00:38 So we have y is equals to 9 .5 inch.
00:43 Now here we have y 3, which is equal to the death of i section divided by 2 plus cn.
00:58 So we have equal to 18 .5 divided by 2 plus 0 .649 .9.
01:06 Which is equal to 9 .25 plus 0 .649.
01:13 So we have equal to 9 .899 inch...
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