00:01
Hello, so here we have a current i which is equal to 1 .08 of plus or minus 0 .02 amps.
00:18
Now we have voltage to be 4 .62 plus minus 0 .01v volts.
00:34
So i want to calculate the uncertainty in the resistance.
00:39
So using oms law r is going to be equal to v over i.
00:48
So let's first, you know, talk about the actual values now.
00:55
Now we're going to be 4 .62 over 1 .08.
01:04
4 .62 divided by 1 .08.
01:12
That's going to be 4 .28 oms.
01:22
So now let's get the uncertainty of that.
01:24
So what we need to do is to get the percentage of certainty in current.
01:33
That's 0 .02 over 1 .08 times 100%.
01:44
That's 2.
01:46
1 .08 plus 1 .85 percent and then the percentage of uncertainty in the voltage x .01 divided by 4 .62 times 100 that's going to be 0 .21 but 0 .22 percent.
02:28
What it means is that the total percentage uncertainty in the resistance is going to be the addition of these two...