0:00
Hi there.
00:01
So for this problem, what we need to do is to calculate, to determine the inductor current when the time is 1 .5 seconds.
00:12
As i can see, you want the procedure in order to do that.
00:16
Well, we already know that the inductance for this is 250 microhenries.
00:23
So that will be 250 times 10 to the minus 3 henries, which is 0 .25 henries.
00:34
And the time, so what we need to do to solve this problem is is 1 divided by this inductance, the integral from 0 to 1 .5 of the expression that we are given, that is the sine of 100 times t integrated over t.
00:56
You already know the solution of this problem.
00:59
You already know that the integral of the sine of 100 times t is the minus cosine of 100 times t, and then this divided by 100.
01:18
In this case, we don't need to consider the constant of integration because our integral is now a defined integral.
01:27
Integral...