The cylinder of a four stroke diesel engine has the...

The cylinder of a four-stroke diesel engine has the following specifications: Brake power 7.5 kW, Speed = 1400 rpm, Indicated mean effective pressure 0.35 MPa, Mechanical efficiency 80%, Maximum gas pressure 3.5 MPa. The cylinder liner and head are made of grey cast iron FG 260 (Sut 260 N/mm² and u 0.25). The studs are made of plain-carbon steel 40C8 (Syt 380 N/mm²). The factor of safety for all parts is 6. Calculate: bore and length of the cylinder liner, thickness of the cylinder liner, thickness of the cylinder head, size, number, and pitch of studs.

Transcript

00:01 In our question today we are given a cylinder of a four -stroke diesel engine that has the following specifications.

00:07 We need to determine the bore and length of the cylinder liner, the thickness of the cylinder liner, thickness of the cylinder head, and size number of studs that are used in the engine.

00:19 Now given that it is a four -stroke engine, we have n equal to which will be given a 700.

00:31 Now let us first calculate the length of the stroke.

00:36 Now we know that the mechanical efficiency of the engine is given by the brake power divided by the indicated power.

00:47 We are given the mechanical efficiency of 80%.

00:50 Therefore we can rearrange the equation in the form.

00:59 Substating the values we have indicated power to be equal to brake power being 75 upon point eight which gives us the indicated power to be equal to 937 watts respectively now indicated power is given as divided by 16 substituting the values we get 1 .4d multiplied by pi by 4d the whole square that is the area into 700 divided by 16 rearranging the equation in order to solve for value of d we get d cube equal to 9375 multiplied by 60 divided by 0 .35 into 10 to the power 6 solving which we get d cube to be equal to which can be written as 0 .128 meters but we know that the length of the stroke can be given as a product of 1 .4 into value of d.

02:51 Substituting which we get 1 .4 multiplied by 128 millimeters giving us the length to be equal to 179 .2 millimeters respectively.

03:05 Therefore the stroke length is of magnitude 179 .2 millimeters.

03:10 Next we have to calculate the thickness of the cylinder.

03:13 Now we know that hoop stress is expressed as 2d by 2p.

03:32 Subtidating the values we get t.

03:47 Rearranging the equation we get the value of t to be equal to that is 6 .4 millimeters respectively...