The decomposition of acetaldehyde is a second order reaction with a rate constant of 4.71 × 10^-

Question

Nicholas Mogoi · Accepted Answer

First, we need to determine the order of the reaction. The problem states that the decomposition

The decomposition of acetaldehyde is a second order reaction with a rate constant of $4.71 \times 10^{-8} \mathrm{L} \mathrm{mol}^{-1} \mathrm{s}^{-1}$ What is the instantaneous rate of decomposition of acetaldehyde in a solution with a concentration of $5.55 \times 10^{-4}$ $M ?$