00:01
Hi, so we are given that density of flow for the liquid through the pipe is rho is equals to 1 .05 into 10 to the power 3 kgs per meter cube.
00:19
The coefficient of viscosity eta is equals to 2 .084 into 10 to the power minus 3 pascal second and 1 pascal equals to newton per meter square.
00:32
So it doesn't any effect.
00:34
The velocity of the flow is 4 .9 into 10 to the power minus 2 centimeter per second.
00:43
If we convert in meter per second, this will become 4 .9 into 10 to the power minus 4 meters per second.
00:51
Now next, the reynolds number is we have been given 0 .0025.
01:00
So we just have to find out the diameter of the pipe.
01:03
So let get started with solution.
01:07
So first of all, since we know that the formula for reynolds number can be given by density into velocity into diameter divided by the viscosity that is eta.
01:21
So from here we can compute it for the diameter.
01:24
So let's plug in the values.
01:26
So the reynolds number 0 .0025, this will be equals to density is 1 .05 into 10 to the power 3 multiplied by velocity is 4 .9 into 10 to the power minus 4 multiplied by the diameter is we have to find let's put as it is divided by the viscosity is 2 .084 into 10 to the power minus 3...