Question

1:51 AM MOMENTUM... Solution In \( 1 \mathrm{~s} \) the water has an initial (horizontal) momentum \( =50 \times 30=1500 \mathrm{Ns} \) It loses all this momentum as a result of the collision. Final momentum \( =0 \mathrm{Ns} \) \[ \text { Force on wall }=\frac{\Delta p}{t}=\frac{m v-m u}{t}=\frac{0-(-1500)}{1}=1500 \mathrm{kgms}^{-1} \] Assignment 3 1.The diagram of below represents a sphere \( \mathrm{P} \) of mass \( 10 \mathrm{~g} \), attached to a fixed support \( 1.0 \mathrm{~m} \) above a table by means of a string. \( \mathrm{P} \) is held \( 50 \mathrm{~cm} \) above the top of the table. A second identical sphere \( \mathrm{Q} \) rests on the edge of the table in line with the point of support of \( \mathrm{P} \). P is released, and at the bottom of its swing makes an elastic collision with \( \mathrm{Q} \), knocking \( \mathrm{Q} \) off the table top. The table top is \( 1.0 \mathrm{~m} \) above the floor. (a)With what speed does P strike \( Q \) ? (b)With what speed does \( \mathrm{Q} \) leave the table? (c)What is the speed of P immediately after collision with Q? (d)What is the kinetic energy of Q just before it strikes the floor? (e)What is the impulse exerted on \( \mathrm{Q} \) by \( \mathrm{P} \) while they are in contact? (f)If \( \mathrm{P} \) and \( \mathrm{Q} \) were made of material such that they stuck together after impact, find the final height the two will rise above the table Practice problems 1. A trolley of mass \( 100 \mathrm{~kg} \) moving at \( 5 \mathrm{~m} / \mathrm{s} \) hits a stationary trolley of mass \( 200 \mathrm{~kg} \). The collision is perfectly inelastic, so the trolleys stick together after the collision. (a) What is the total momentum before the collision? (b) Apply the conservation of momentum principle to find the velocity of both trolleys after the collision. (c) Calculate the loss in kinetic energy as a result of the collision. Trade all your favourite products or find new opportunities on the world's financial...

          1:51 AM
MOMENTUM...
Solution

In \( 1 \mathrm{~s} \) the water has an initial (horizontal) momentum \( =50 \times 30=1500 \mathrm{Ns} \)
It loses all this momentum as a result of the collision.
Final momentum \( =0 \mathrm{Ns} \)
\[
\text { Force on wall }=\frac{\Delta p}{t}=\frac{m v-m u}{t}=\frac{0-(-1500)}{1}=1500 \mathrm{kgms}^{-1}
\]

Assignment 3
1.The diagram of below represents a sphere \( \mathrm{P} \) of mass \( 10 \mathrm{~g} \), attached to a fixed support \( 1.0 \mathrm{~m} \) above a table by means of a string. \( \mathrm{P} \) is held \( 50 \mathrm{~cm} \) above the top of the table. A second identical sphere \( \mathrm{Q} \) rests on the edge of the table in line with the point of support of \( \mathrm{P} \). P is released, and at the bottom of its swing makes an elastic collision with \( \mathrm{Q} \), knocking \( \mathrm{Q} \) off the table top. The table top is \( 1.0 \mathrm{~m} \) above the floor.
(a)With what speed does P strike \( Q \) ?
(b)With what speed does \( \mathrm{Q} \) leave the table?
(c)What is the speed of P immediately after collision with Q?
(d)What is the kinetic energy of Q just before it strikes the floor?
(e)What is the impulse exerted on \( \mathrm{Q} \) by \( \mathrm{P} \) while they are in contact?
(f)If \( \mathrm{P} \) and \( \mathrm{Q} \) were made of material such that they stuck together after impact, find the final height the two will rise above the table
Practice problems
1. A trolley of mass \( 100 \mathrm{~kg} \) moving at \( 5 \mathrm{~m} / \mathrm{s} \) hits a stationary trolley of mass \( 200 \mathrm{~kg} \). The collision is perfectly inelastic, so the trolleys stick together after the collision.
(a) What is the total momentum before the collision?
(b) Apply the conservation of momentum principle to find the velocity of both trolleys after the collision.
(c) Calculate the loss in kinetic energy as a result of the collision.
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1:51 AM
MOMENTUM...
Solution

In 1 s the water has an initial (horizontal) momentum =50 × 30=1500 Ns
It loses all this momentum as a result of the collision.
Final momentum =0 Ns

Force on wall =(Δ p)/(t)=(m v-m u)/(t)=(0-(-1500))/(1)=1500 kgms^-1

Assignment 3
1.The diagram of below represents a sphere P of mass 10 g, attached to a fixed support 1.0 m above a table by means of a string. P is held 50 cm above the top of the table. A second identical sphere Q rests on the edge of the table in line with the point of support of P. P is released, and at the bottom of its swing makes an elastic collision with Q, knocking Q off the table top. The table top is 1.0 m above the floor.
(a)With what speed does P strike Q ?
(b)With what speed does Q leave the table?
(c)What is the speed of P immediately after collision with Q?
(d)What is the kinetic energy of Q just before it strikes the floor?
(e)What is the impulse exerted on Q by P while they are in contact?
(f)If P and Q were made of material such that they stuck together after impact, find the final height the two will rise above the table
Practice problems
1. A trolley of mass 100 kg moving at 5 m / s hits a stationary trolley of mass 200 kg. The collision is perfectly inelastic, so the trolleys stick together after the collision.
(a) What is the total momentum before the collision?
(b) Apply the conservation of momentum principle to find the velocity of both trolleys after the collision.
(c) Calculate the loss in kinetic energy as a result of the collision.
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Added by Kai K.

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