The diameter of a hydrogen atom is 212 pm. Find the length in kilometers of a row of $6.02 \times 10^{23}$ hydrogen atoms. The diameter of a ping pong ball is 4.0 $\mathrm{cm} .$ Find the length in kilometers of a row of $6.02 \times 10^{23}$ ping pong balls.
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Step 1
\[ 1 \text{ pm} = 1 \times 10^{-12} \text{ m} \] Given the diameter of a hydrogen atom is 212 pm: \[ 212 \text{ pm} = 212 \times 10^{-12} \text{ m} = 2.12 \times 10^{-10} \text{ m} \] Show more…
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The diameter of a hydrogen atom is 212 pm. Find the length in kilometers of a row of 6.02 * 1023 hydrogen atoms. The diameter of a ping pong ball is 4.0 cm. Find the length in kilometers of a row of 6.02 * 1023 ping pong balls.
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