The diffusion coefficients for Ni in Fe are given at two temperatures: \begin{tabular}{|c|c|} \hline $T$ (K) & $D$ (m$^2$/s) \\ \hline 1473 & $2.2 \times 10^{-15}$ \\ \hline 1673 & $4.8 \times 10^{-14}$ \\ \hline \end{tabular} (a) Determine the values of $D_0$ and the activation energy $Q_d$ in eV/atom. (3 points) (b) Determine D at 1300 $^\circ$C. (2 points)
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314 J/(mol*K)), and T is the temperature in Kelvin. We have two sets of data points: (1473 K, 2.21x10^-15 m^2/s) and (1673 K, 4.81x10^-14 m^2/s). Let's use the first set of data points to solve for D0 and Qa: 2.21x10^-15 = D0 * exp(-Qa / (8.314 * 1473)) Taking Show more…
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The diffusion coefficients for nickel in iron are given at two temperatures, as follows: \begin{tabular}{cc} \hline $\boldsymbol{T}(\boldsymbol{K})$ & $\boldsymbol{D}\left(\mathrm{m}^{2} / \mathrm{s}\right)$ \\ \hline 1473 & $2.2 \times 10^{-15}$ \\ \hline 1673 & $4.8 \times 10^{-14}$ \\ \hline \end{tabular} (a) Determine the values of $D_{0}$ and the activation energy $Q_{d^{\prime}}$ (b) What is the magnitude of $D$ at $1300^{\circ} \mathrm{C}(1573 \mathrm{~K}) ?$
The diffusion coefficients for nickel in iron are given at two temperatures: $$\begin{array}{cc} \boldsymbol{T}(\boldsymbol{K}) & \boldsymbol{D}\left(\boldsymbol{m}^{2} / \boldsymbol{s}\right) \\ \hline 1473 & 2.2 \times 10^{-15} \\ 1673 & 4.8 \times 10^{-14} \end{array}$$ (a) Determine the values of $D_{0}$ and the activation energy $Q_{d}$ (b) What is the magnitude of $D$ at $1300^{\circ} \mathrm{C}$ $(1573 \mathrm{K}) ?$
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