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Hello everyone.
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In this question we are given that the rate of effusion of noble gas is twice as that of the rate of effusion of oxygen.
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That is a noble gas effuses at a rate of twice as that of oxygen.
00:20
What we have to find is which noble gas is that.
00:24
What is the nature of that noble gas? we have to find which noble gas effuses twice as that.
00:30
Of oxygen.
00:31
So in the solution we know rate of effusion is inversely proportional to the square root of molar mass of the gas.
01:05
Right.
01:07
Now let ro2 be rate of effusion of oxygen are n is rate of effusion of noble gas.
01:50
M .o2 will be molar mass of oxygen and nn be the molar mass of noble gas.
02:24
In our question, we are asked to predict the noble gas which rate of effusion is twice of oxygen.
02:32
So what we will do is we will find the molar mass of the noble gas.
02:36
From that molar mass, we can easily predict the type of the noble gas on which noble gas is present.
02:43
So we will write the formula as r of o2 divided by r of n is equals to what we know, it is inversely proportional to the molar mass of gases.
02:58
So r of o2 will be inversely proportional to m of o2 and r of n will be mostly proportional to m of n, right? now we know r n is equal to twice of r o2.
03:22
So r .o2 divided by twice of r02 will be equals to mn...