Question

The displacement from equilibrium of an oscillating mass attached to a spring is given by $y(t) = 4 \cos 3\pi t$ where y is measured in inches and t in seconds. Find the displacement at the times indicated in the table. (Round your answers to three decimal places.) \begin{tabular}{|c|c|} \hline t & y(t) \\ \hline 0 & \\ 0.25 & \\ 0.50 & \\ 0.75 & \\ 1.00 & \\ 1.25 & \\ \hline \end{tabular}

          The displacement from equilibrium of an oscillating mass attached to a spring is given by $y(t) = 4 \cos 3\pi t$ where y is measured in inches and t in seconds. Find the displacement at the times indicated in the table. (Round your answers to three decimal places.)

\begin{tabular}{|c|c|}
\hline
t & y(t) \\
\hline
0 & \\
0.25 & \\
0.50 & \\
0.75 & \\
1.00 & \\
1.25 & \\
\hline
\end{tabular}

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The displacement from equilibrium of an oscillating mass attached to a spring is given by y(t) = 4 cos 3π t where y is measured in inches and t in seconds. Find the displacement at the times indicated in the table. (Round your answers to three decimal places.)

t y(t)

0

0.25

0.50

0.75

1.00

1.25

Added by Trinidad B.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Adi S

02/07/2023

Step 1

For t=0.25: y(0.25) = 4cos(3π(0.25)) = 4cos(0.75π) ≈ 4cos(2.356) ≈ 4(-0.707) ≈ -2.828 For t=0.50: y(0.50) = 4cos(3π(0.50)) = 4cos(1.5π) ≈ 4cos(4.712) ≈ 4(0) = 0 For t=0.75: y(0.75) = 4cos(3π(0.75)) = 4cos(2.25π) ≈ 4cos(7.068) ≈ 4(0.707) ≈ 2.828 For Show more…

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The displacement from equilibrium of an oscillating mass attached to a spring is given by y(t)=4cos3pi t where y is measured in inches and t in seconds. Find the displacement at the times indicated in the table. (Round your answers to three decimal places.) able[[t,y(t) displacement at the times indicated in the table.(Round your answers to three decimal places.) y(t) 0.25 0.50 0.75 1.00 1.25 4WW- WWWW y>o Equilibrium,y=0 y<o

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