Instantaneous velocity at t=2s: We need to find the first derivative of the displacement function with respect to time (t) and then evaluate it at t=2s.
x(t) = 18t + 5t^2
dx/dt = v(t) = 18 + 10t
Now, we evaluate v(t) at t=2s:
v(2) = 18 + 10(2) = 18 + 20 =
Show more…