00:01
For this exercise, we are told that we want the dose of a drug to have a mean of 47 .89 and a variance of 0 .03.
00:11
And we are also told that we can assume that the dosage is normally distributed.
00:19
And to check on this, we have a sample of size 25.
00:23
Sample variance is 0 .0069.
00:26
And we are asked to test at a significance level of 0 .01.
00:29
If there is evidence that the variance is less than the desired amount at 0 .03.
00:39
So we can say step one is the no hypothesis can be that the variance is what it's supposed to be, 0 .03, and the alternative hypothesis is that the variance is less than 0 .03.
01:04
So these are the hypotheses for this test.
01:09
And then for step two, we are asked to find the critical value or critical values.
01:16
Now, if we look at the alternative hypothesis for this test, it is less than, which indicates that this is a one -tailed or left -tailed test.
01:26
So there is going to be only one critical value...