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Hi there.
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So for this problem, we have a person whose weight is given and that is 584 newtons and we need to find for this problem the normal force asserted by the floor on each hand and each food.
00:26
So we need to find that.
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We're going to call the normal force of the food as an f and the normal force of the hand as an h.
00:37
So we need to obtain that.
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And assuming that the person holds this position that is shown in the figure.
00:49
So the first thing that we can do is to draw all of the forces that are acting on this.
00:58
So we know that we have the normal force of the feet that is perpendicular to the surface, we call this an f.
01:09
We also have a normal force of the hands.
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We call this nh.
01:15
And we have the weight, which is pointing downward, and it comes from its gravitational center or its center of mass.
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Now, so the lever arms, is the rotational axis perpendicular to the plane of the paper at the place where the person's toes touch the flow.
01:49
Since the person is in equilibrium, the sum of the forces must be zero, and we know that the sum of tors must be zero as well.
02:00
So what we can do first is to apply nietzschev's law.
02:04
So we're going to assume the forces in this case.
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Those forces are the normal force of the feet plus the normal force of the hands minus the weight.
02:23
And this should be equal to zero because the problem sets that we need to assume that the person is holding this position.
02:30
So we are in the equilibrium.
02:32
Now, to do the sum of forces, we need to remember that counter -cloudwise torts, are positive and using the axis and the lever arms chosen in this drawing we can zoom all of the towards in this case this will be so we have the normal force sorry the weight times the length of the weight to the position of rotation and we also have and so the position of rotation as you can see from there to here we have this position in here that is the position of the from the from the point of rotation to the to the application of the force so that is l that is the distance to that point it is 0 .84 meters now, the other force that made torque is the normal force in the hands...