00:01
In this problem, the drawing shows a square, each side of which has a length of l equals to 0 .250 meters.
00:12
Two different positive charges, q1 and q2 are fixed at a corners of the square.
00:17
Right.
00:20
Find the electric potential energy of a third charge, q3, which is having a charge minus 3 .00 into 10 to the power minus.
00:31
9 hula placed at corner a and at corner b right so first of all we'll see when we'll when we'll put this charge q3 at a this is for the first scenario right and when it is placed at b so this is second scenario all right so uh this is nothing but this is here denoted by uh we need to find out e p e a that is is electric potential energy at a right say epa e v right so this is so simple as that we know the length this is 0 .250 and let us suppose this value let us say this is r2 this distance l is equal to r2 here and this is r4 this value right and this is r3 this distance right and this is r1 this is r1 right.
01:36
So this becomes so simple.
01:38
Right.
01:39
So we will just add electric potential energy due to this charge whenever this was placed.
01:44
Only just see a, q1 and q2.
01:48
Just see this.
01:49
So we have, we just have to find this electric potential energy at this point.
01:53
So this will be, if it is asked, it is asked the epa of a third charge, right? so that means we know that potential, any point is similarly q by r right so this constant is always here right so remember from this if we want to calculate for the third charge we have to multiply this q3 that's why we have multiplied here so here epea is given by k q3 into that is in bracket q1 r1 plus q2 by r2 right so in a square we we know that this diagonal value is root to l that is root 2 side so, the square, right? so when we will solve this, we will put all the values, that is the k is a constant, right, which is whose value is 9 into 10 to the power 9.
02:51
Then q3 is minus 3 .00 into 10 to the power minus 9.
02:57
Then we will multiply it by, in bracket, it is 1 .50 into 10 to the power minus 9 upon root 2 into 0 .2 into 0 .2 .2...