00:01
Hello everyone, we are going to understand this question here, give it in the question, given, refractive index of rectangular block, refractive index of rectangular block, that is represented by n1, which is 1 .52, 1 .52.
00:46
And it is surrounded by the carbon dioxide, it is surrounded by the liquid that is called carbon disulfide.
00:56
Refractive index of carbon dioxide or refractive index of liquid refractive index of liquid carbon dioxide that is represented by n2 which is 1 .63 here ray of light is incident at the point a so angle of incident at point a angle of incidence at a that is represented by ia which is 30 degree let the refraction at the point a be let the angle of refraction at the point a b ira let the angle of refraction angle of refraction at a that is represented by r a that is represented by r a which is 30 degree.
02:19
Now we have to find the critical angle.
02:26
We have to find at what angle refraction does at the ray leaves at the point b.
02:30
So here we have to find the angle of, what angle of refraction does the ray leave the glass at point b? so we have to find the angle of refraction at the point b.
02:47
Now let the angle of refraction, at b, the angle of refraction at b, that is represented by rb, which we have to find.
03:08
Now applying snell's rule.
03:13
Now applying snell's rule, applying snell's rule, that is, sine ia upon sine r a upon sine r a upon sine r a is equal to n2 upon n1.
03:42
So from this we will get sine r a is equal to n1 upon n2 into sine ia now substituting the value in this here value of n1 is 1 .5 to sorry here value of n1 is 1 .63 because ray of light is entering from carbon dioxide 5 to glass but here we we have we did a mistake in the notation.
04:22
Let's corrected this one is n1 sorry n2 reflective index of rectangular block this is n2 and this one is n1 by mistakenly i named it as n1 and n2 now it's corrected right now now substituting the value in this so 1 .63 upon 1 .52 into sine 30 after doing further calculation we will get 1 .63 upon 2 into 1 .52 because sine 30 is 1 upon 2 that is equal to sine r a again we can write r a is equal to sine inverse r a is equal to sine inverse 1 .63 upon 2 into 1 .52 now doing further calculation so we will get r a is equal to ra means angle of refraction at the point a that is represented by ra...