00:01
Hello student, here we are asked to find the current in the wires.
00:07
So, here the magnetic force between the wires is repulsive and that acts perpendicular to the length of the wire.
00:18
So, that is f p and the tension in the cable let's say this is p.
00:26
So, its component along perpendicular to the length is along the vertical direction is p cos 15 degree and its component along this direction is p sin 15 degree.
01:05
Now f p equals to and the weight of the wire acts downward f p equals to that is the magnetic force between the wire is u naught i square l where l is the length of the wire divided by 2 pi d.
01:27
Now at theta equals to 15 degree we have an equilibrium.
01:37
So, we can write m g equals to p cos 15 degree here m g equals to t cos 15 degree and we can also write f p equals to p sin 15 degree.
01:56
Therefore tan 15 degree equals to f p by m g.
02:03
So, that is mu naught i square l by 2 pi d into into 1 by 1 by m g that is from this i square can be calculated as tan 15 degree into 2 pi d into m d l divided by mu naught...