The Earth is 1.49 x 1011 m from the Sun. If the Earth requires 365.25 days to go once around the Sun, what is the magnitude of the centripetal force acting on the Earth?
Added by Walter C.
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T = 365.25 days × 24 h/day × 3600 s/h = 31,557,600 s Show more…
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Rakhshan S.
The Earth moves uniformly around the sun once every 365.25 days. The radius of the orbit is approximately 1.5 x 10^11 meters. The Earth has a mass of 6.0 x 10^ 24 kgs. Recalling Newton's second law compute the centripetal force on the Earth (in Newtons) as it moves around the Sun. The answer is n x 10^22 Newtons, where n is a number between 0 and 9.999. Enter n to two significant figures (one decimal place). For example, if your answer is 1.3 x 10^22, enter '1.3' as your response.
Nishant K.
A. The Earth has a mass of 5.97 * 1024 kg and the Sun has a mass of 2.00 * 1030 kg. If they are separated by a distance of 1.50 * 108 km, what is the force (in N) between the Earth and the Sun? (Enter your answer in scientific notation: 1.23E12 means 1.23 * 1012). B. Repeat the previous problem using centripetal forces. Assume the Earth travels in a perfect circle around the Sun, with masses and distances given above, and takes 365.25 days to complete a complete circle. What is the centripetal force (in N) acting on the Earth? (Think about why and by how much the answers to these two questions differ.)
Sam S.
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