Question

The electric potential difference across the membrane of a body cell is +0.076 V (higher on the outside than on the inside). The cell membrane is 8.3×10^(-9) m thick. a. Determine the magnitude of the E vector field through the cell membrane. b. Determine the direction of the E vector field through the cell membrane (in or out).

Name: the electric potential difference across the membrane of a body cell is 0076 vv higher on the outside than on the inside the cell membrane is 83109 mm thick a determine the magnitude of the 42715
Uploaded: 2022-05-26T14:00:35-08:00
Duration: 2 min 21 s
Channel: Adi S
Description: the electric potential difference across the membrane of a body cell is 0076 vv higher on the outside than on the inside the cell membrane is 83109 mm thick a determine the magnitude of the 42715

          The electric potential difference across the membrane of a body cell is +0.076 V (higher on the outside than on the inside). The cell membrane is 8.3×10^(-9) m thick.
a. Determine the magnitude of the E vector field through the cell membrane.
b. Determine the direction of the E vector field through the cell membrane (in or out).

Added by Amanda H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

05/26/2022

Step 1

Step 1: Calculate the magnitude of the electric field through the cell membrane using the formula E = V / l, where V is the potential difference and l is the thickness of the membrane. Show more…

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The electric potential difference across the membrane of a body cell is +0.076 V (higher on the outside than on the inside). The cell membrane is 8.3×10^(-9) m thick. a. Determine the magnitude of the E vector field through the cell membrane. b. Determine the direction of the E vector field through the cell membrane (in or out).