The empirical formula part is where I need help.
Use the following data:
A. Mass of crucible: 12.214g
B. Mass of crucible and hydrate: 13.250g
C. Mass of crucible and anhydrous salt: 12.885g
Note: We are using CuSO instead of MgSO.
Calculate the molar mass of CuSO and write its value here: 159.61 g/mol.
Mass of anhydrous salt: 12.214g + x = 12.885g = 0.671g
Moles of anhydrous salt: 4.20 * 10^3 / 1000 = 4.20 mol
Mass of water lost: 1.036 - 0.671 = 0.365g
Molar mass of water: 18.02 g/mol
Moles of water: 0.02026 mol
Divide the moles of water by the moles of anhydrous salt to find n, the moles of water per mole anhydrous salt.
n = 0.02026 / 4.20 = 0.00483
The empirical formula for our hydrate is CuSO * 0.00483 H2O, where n is the number you just found. Record the empirical formula for the copper(1) sulfate hydrate below.
Formula of hydrate: CuSO * 0.00483 H2O