Question

The energies of the valence extit{d} orbitals on the iron atom in the octahedral [FeF$_6$]$^{4-}$ complex are split according to the electron box level diagram below. (Note: the extit{d} orbitals are labeled with just their subscript, to make the labels easier to read.) Complete the diagram by adding the correct number of electrons to each orbital.

          The energies of the valence 	extit{d} orbitals on the iron atom in the octahedral [FeF$_6$]$^{4-}$ complex are split according to the electron box level diagram below. (Note: the 	extit{d} orbitals are labeled with just their subscript, to make the labels easier to read.)
Complete the diagram by adding the correct number of electrons to each orbital.

The energies of the valence extitd orbitals on the iron atom in the octahedral [FeF6]^4- complex are split according to the electron box level diagram below. (Note: the extitd orbitals are labeled with just their subscript, to make the labels easier to read.)
Complete the diagram by adding the correct number of electrons to each orbital.

Added by Daniel B.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Ivan Kochetkov

01/08/2023

Step 1

First, we need to determine the number of electrons in the d orbitals of the iron atom. Iron (Fe) has an atomic number of 26, which means it has 26 electrons in its neutral state. However, in the [FeF6]2- complex, the iron atom has lost 2 electrons, so it has 24 Show more…

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