00:01
The hydrogen and oxygen fuel reaction is h2 gas plus half o2 gas and it forms h2o liquid.
00:14
This is your hydrogen and oxygen fuel reaction.
00:19
We know that delta g node can be written as minus nf e node cell.
00:24
So by using this expression we can calculate e node cell is equal to delta g0 upon minus nf.
00:32
Number of electrons transferred in the following reaction is 2.
00:36
So, and delta g0 value given in the question is minus 237 .191 kilojoules.
00:42
So convert this kilojoule into joules into by multiplying it with 1000 into minus 2 into value of f is faradis constant 96485 .33.
00:56
Negative and negative got cancelled and from here you will get the e0 cell value which is equal to 1 .22.
01:02
To 9 volt.
01:03
This is the value of e node.
01:05
Now by applying nursed equation, we can write by nursed equation e cell is equals to e node cell minus rt upon nf natural log concentration of reactant upon concentration of product.
01:28
And here in the reaction, reactant, concentration of product is liquid.
01:33
So it will be taken as one concentration of product upon concentration of reactant so at reactant side pressure of h2 and pressure of o2 to the power half it is present so it will be written like this so e -cell will be equals to e node cell 1 .229 minus rt upon nf natural law 1 upon 1 into 1 because in the question partial pressure of h2 and o 2 given is 1 so this whole term will become 0 because natural log of 1 is what is 0.
02:10
So e -cell is equal to e0 cell which is equal to 1 .229 volt.
02:18
From here we got our e -cell value which is equivalent to e -0 cell.
02:24
Now delta g can be written as minus nf e -cell...