The energy of a K?electron in tungsten is ?20 KeV and of an L?electron is ?2 KeV. Find the wavelength of X? rays emitted when there is electron jump from L to K shell.
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Step 1
Given: Energy of K-electron (EK) = 20 KeV Energy of L-electron (EL) = 2 KeV Energy difference (ΔE) = EK - EL ΔE = 20 KeV - 2 KeV ΔE = 18 KeV Show more…
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