The enthalpy change for the following reaction is -136 kJ. Using bond energies, estimate the H-O bond energy in H2O2(g). H2(g) + O2(g) → H2O2(g) ΔH = -136 kJ/mol
Added by Timothy A.
Step 1
First, we need to break the bonds in the reactants. The bond energy of H-H in H2 is about 436 kJ/mol and the bond energy of O=O in O2 is about 498 kJ/mol. So, the total energy required to break the bonds in the reactants is 436 + 498 = 934 kJ/mol. Show more…
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