Question

The enthalpy of reaction for the neutralization reaction between sulfuric acid and sodium hydroxide is -111.7 kJ. If 150 mL of 3.0 M sodium hydroxide is mixed with 100.0 mL of 4.0 M sulfuric acid, what is the temperature change of the mixture? **Assume that the densities of the solutions are 1.00 g/mL and the specific heat of the solution is 4.18 J/(g* oC).

Name: the enthalpy of reaction for the neutralization reaction between sulfuric acid and sodium hydroxide is 1117 kj if 150 ml of 30 m sodium hydroxide is mixed with 1000 ml of 40 m sulfuric acid 65358
Uploaded: 2022-06-03T18:01:11-08:00
Duration: 2 min 39 s
Channel: Sri K
Description: the enthalpy of reaction for the neutralization reaction between sulfuric acid and sodium hydroxide is 1117 kj if 150 ml of 30 m sodium hydroxide is mixed with 1000 ml of 40 m sulfuric acid 65358

          The enthalpy of reaction for the neutralization reaction between
sulfuric acid and sodium hydroxide is -111.7 kJ. If 150 mL of 3.0 M
sodium hydroxide is mixed with 100.0 mL of 4.0 M sulfuric acid,
what is the temperature change of the mixture? **Assume that the
densities of the solutions are 1.00 g/mL and the specific heat of
the solution is 4.18 J/(g* oC).

Added by Danielle T.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

06/03/2022

Step 1

Given: Volume of NaOH solution = 150 mL Molarity of NaOH solution = 3.0 M Volume of H2SO4 solution = 100.0 mL Molarity of H2SO4 solution = 4.0 M First, calculate the moles of NaOH: Moles of NaOH = Volume (L) x Molarity Moles of NaOH = 0.150 L x 3.0 mol/L Moles of Show more…

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The enthalpy of reaction for the neutralization reaction between sulfuric acid and sodium hydroxide is -111.7 kJ. If 150 mL of 3.0 M sodium hydroxide is mixed with 100.0 mL of 4.0 M sulfuric acid, what is the temperature change of the mixture? **Assume that the densities of the solutions are 1.00 g/mL and the specific heat of the solution is 4.18 J/(g* oC).