The equation for the reaction of iron and oxygen gas to form rust (Fe2O3) is written as (7.5,7.6

Name: The equation for the reaction of iron and oxygen gas to form rust (Fe2O3) is written as (7.5,7.6,7.7,7.9) 4 Fe(s)+3 O2(g) ⟶ 2 Fe2O3(s) Δ H=-1.7 × 10^3 kJ a. How many kilojoules are released when 2.00 g of Fe reacts? b. How many grams of rust form when 150 kJ are released?
Uploaded: 2023-07-05T06:01:59-08:00
Duration: 2 min 41 s
Channel: Madhur L
Description: The equation for the reaction of iron and oxygen gas to form rust (Fe2O3) is written as (7.5,7.6,7.7,7.9) 4 Fe(s)+3 O2(g) ⟶ 2 Fe2O3(s) Δ H=-1.7 × 10^3 kJ a. How many kilojoules are released when 2.00 g of Fe reacts? b. How many grams of rust form when 150 kJ are released?

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Penny Riley · Accepted Answer

First, we need to find the moles of Fe in 2.00 g of Fe. The molar mass of Fe is 55.85 g/mol. So,

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