00:01
Hello, we can give it an equation in the form y equals 6 sine 0 .02x plus 4 .05 t as an equation of a wave.
00:28
We compare this to the general equation of a wave which is a sine kx plus w t and by we can see that amplitude is 6 centimeters.
00:56
For b, we have to find a wavelength.
01:00
We see again that k by comparison, the coefficient of x is k, which is 0 .0 2 pi.
01:07
So k equals 0 .0 2 pi.
01:11
But we know that k is given by 2 pi over lambda.
01:15
Therefore 0 .0 2 pi, which is k, equals 2 pi over lambda.
01:23
Making lambda the subject we get 100 meters.
01:30
C, we have to find frequency and we know that frequency is two.
01:38
Omega equals 2 pi f.
01:40
So we compare this side of the equation and realize that our omega is equal to 4 .0 pi.
01:47
So omega equals 4 .0 pi.
01:52
But omega is 2 pi f.
01:54
So omega equals 4 .0 pi.
01:57
This implies that 2 pi f equals 4 .0 pi because omega equals 2 pi f so f then becomes 4 .0 pi over 2 pi which is 2 hertz velocity is frequency times wavelength which is 100 times 2 so 200 meters per second e because of the plus sign the wave travels to the left...