The equation of common tangents to the parabola y^2 = 8x and hyperbola 3x^2 - y^2 = 3 is: A. 2x ± y + 1 = 0 B. 2x ± y - 1 = 0 C. x ± 2y + 1 = 0 D. x ± 2y - 1 = 0
Added by Adam H.
Step 1
The equation of the parabola is $y^2 = 8x$. Differentiating both sides with respect to $x$, we get: $2y \frac{dy}{dx} = 8$ So, the slope of the tangent to the parabola is: $\frac{dy}{dx} = \frac{8}{2y} = \frac{4}{y}$ Show more…
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