The equilibrium constant, Kc, for the reaction H2 (g) + I2 (g) <> 2HI (g) is 54 at 425 ºC. If the equilibrium mixture contains 0.030 M HI and 0.015 M I2 , the equilibrium concentration of H2 is?
Added by Angela C.
Step 1
Step 1: Write the equilibrium constant expression for the reaction: Kc = [HI]^2 / ([H2] * [I2]) Show more…
Show all steps
Your feedback will help us improve your experience
Ronald Prasad and 80 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The equilibrium constant, Kc, for this reaction is 55. H2(g) + I2(g) ⇌ 2HI(g) If the equilibrium mixture contains 0.016 M I2 and 0.031 M HI, what is the molar concentration of H2?
David C.
In a gas-phase equilibrium mixture of H2, I2, and HI at 500 K, [HI] = 2.21 mmol/L and [I2] = 1.46 mmol/L. Given the value of the equilibrium constant, Kc, is 160, calculate the equilibrium concentration of H2 for this reaction: H2(g) + I2(g) ⇌ 2HI(g).
Chareen G.
Consider the reaction H2 + I2 2HI for which Kc = 44.0 at a high temperature. If an equimolar mixture of reactants gives the concentration of the product to be 0.50 M at equilibrium, determine the equilibrium concentration of the hydrogen.
Ronald P.
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD