The evaporation of water is what cools your body. Calculate the heat required in kJ to evaporate 300 g of human sweat at 25 degrees C. (Assume sweat is pure water in this case. Ha!). Careful: See footnote in Table 3.1 Answer is not 771. 795
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Evaporating sweat cools the body because evaporation is an endothermic process: $$ \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{H}_{2} \mathrm{O}(g) \quad \Delta H_{\mathrm{ren}}^{\mathrm{e}}=+44.01 \mathrm{kJ} $$ Estimate the mass of water that must evaporate from the skin to cool the body by $0.50^{\circ} \mathrm{C}$ . Assume a body mass of 95 $\mathrm{kg}$ and assume that the specific heat capacity of the body is 4.0 $\mathrm{J} / \mathrm{g} \cdot^{\circ} \mathrm{C}$ .
Evaporating sweat cools the body because evaporation is an endothermic process: Estimate the mass of water that must evaporate from the skin to cool the body by 0.50 C. Assume a body mass of 95 kg and assume that the specific heat capacity of the body is 4.0 J>g # C.
David C.
Evaporating sweat cools the body because evaporation is endothermic and absorbs $2.44 \mathrm{kJ}$ per gram of water evaporated. Estimate the mass of water that must evaporate from the skin to cool a body by $0.50^{\circ} \mathrm{C}$, if the mass of the body is $95 \mathrm{kg}$ and its heat capacity is $4.0 \mathrm{J} / \mathrm{g}^{\circ} \mathrm{C}$ (Assume that the heat transfer is $100 \%$ efficient.)
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