00:01
Hello students in this question, we have given the parameter of the exponential random variable, which is lambda is equal to 4.
00:08
That means we have given that the random variable x follows the exponential distribution with parameter lambda is equal to 4.
00:16
Now by using this in the first question, we have to write the formula for the pdf that is probability density function for the waiting time x.
00:26
So now x is the random variable which follows the exponential then the pdf for the waiting time is f of x is equal to lambda into e raised to minus lambda into x and now this is equal to 4 into e raised to minus 4 into x.
00:55
So this is the pdf for the exponential distribution.
00:57
Then in the next question, we have to calculate the mean waiting time and also variance of the waiting time.
01:04
So now we know that the mean waiting time of the exponential distribution mean waiting time is equal to 1 divided by lambda that is equal to 1 divided by 4 is equal to 0 .25.
01:22
Then the variance is 1 divided by lambda square, which is equal to 1 divided by 16 and then in the next question, we have to calculate the probability that the waiting time will be less than 15 minutes.
01:39
So probability of x is less than 15.
01:43
Now, we know the cdf that is the cumulative distribution function of the exponential.
01:50
So cdf of the exponential distribution is capital f of x that is equal to probability of x is less than or equal to x is equal to 1 minus e raised to minus lambda into x...