Question

The expression $ \left( \frac{2a^{-6}}{3b^{-1/5}} \right)^{-1} $ equals $na^r/b^t$ where n, the coefficient, is: r, the exponent of a, is: t, the exponent of b, is:

          The expression \( \left( \frac{2a^{-6}}{3b^{-1/5}} \right)^{-1} \) equals $na^r/b^t$ where
n, the coefficient, is:
r, the exponent of a, is:
t, the exponent of b, is:

The expression ( (2a^-6)/(3b^-1/5))^-1 equals na^r/b^t where
n, the coefficient, is:
r, the exponent of a, is:
t, the exponent of b, is:

Added by Valerie W.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Adi S

06/12/2023

Step 1

Step 1: Simplify the expression using the rule of exponents: $$(\frac{a}{b})^n = \frac{a^n}{b^n}$$ Show more…

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The expression equals na^r/b^t where n, the coefficient, is: r, the exponent of a, is: t, the exponent of b, is: $$(\frac{2a^{-6}}{3b^{-1/5}})^{-1}$$

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The expression \( \left( \frac{2a^{-6}}{3b^{-1/5}} \right)^{-1} \) equals $na^r/b^t$ where n, the coefficient, is: r, the exponent of a, is: t, the exponent of b, is:

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