00:01
In this example, i'm going to be looking at centripetal motion, so some rotational motion, something going around in a circle.
00:09
And what we have is a train car traveling at 6, 216 kilometers per hour or 60 meters per second.
00:20
It's coming up on a curve.
00:22
Now that we want our maximum acceleration to be equal to 0 .05g, where g is the acceleration due to gravity.
00:30
So we want to find the radius of curvature of this curve corner that this train will be going around to satisfy this requirement.
00:39
All right.
00:39
So what do we know about centriple acceleration? we know acceleration equals v squared over r.
00:48
Or r equals v squared over a.
00:53
And we have v equals 60 meters per second squared.
01:01
Over 0 .05 times 9 .81 meters per second.
01:07
Right, and we can solve that for r to get r equals 7 .34 kilometers.
01:16
All right, so it's a pretty, pretty shallow curve to adhere to our requirements for acceleration.
01:24
Next, we're going to assume that our radius of curvature equals 1 .19 kilometers.
01:32
Time we want to find a velocity that will fit my requirements of the same acceleration of 0 .05g...