00:01
For this problem to begin, in part a, we'll have that our decision rule is going to be that we reject the null hypothesis if our t statistic is less than the negative critical value for, now it's going to be our sample size minus 1 in terms of degrees of freedom, so that's 7 degrees of freedom, and a one tail proportion of 0 .01.
00:25
We'll find that using a table of values here.
00:28
So 7 degrees of freedom, 0 .01 and one tail, find the critical value to be 2 .998.
00:35
So we reject the null if t is less than negative 2 .998.
00:42
That's our answer for part a.
00:44
Then for part b, for computing our test statistic, the first thing that we would need to do is find our sample mean difference.
00:50
Now as you can see here, i've gone ahead and calculated out the individual pair differences ahead of time, then the sample mean difference and sample standard deviation of differences.
00:59
If you're doing this kind of problem, i'm assuming that calculating a sample mean and a sample standard deviation is old hat by now...