00:01
Hi, in this question we have to develop a radix to dif that is the decimation in frequency.
00:08
So in ftt algorithm, it is given by fast fourier transform.
00:16
So here for n is equal to 8.
00:19
Now we have to so first we have to arrange the sequence xn in bit reversed order.
00:29
So we have it is so order it is given by it is x of 0, x of 4, so x of 2, x of 6, x of 1, x of 5 and x of 3 and x of 7.
00:50
Then we have to perform n by 2 that is 4 stage of butterfly butterfly computation where we have so for the first case stage 1 that is butterfly with w power 0.
01:14
So it can be given by it is so compute so compute x of 0 is equal to x of 0 plus x of 4.
01:25
Similarly, x of 4 is equal to x of 0 minus x of 4 and also x of 2 is given by x of 2 plus x of 6 and similarly for x of 6 we can write it as x of 2 minus x of 2.
01:44
Then we have x of 1 is given by x of 1 plus x of 5.
01:50
So we can write x of 5 as x of 1 minus x of 5.
01:55
Then we have x of 3 can be written as x of 3 plus x of 7.
02:02
Similarly, we can write for x of 7 can be written as x of 3 minus x of 7.
02:08
Now for stage 2 we have the butterfly with omega power 0 and w power 0.
02:17
So we have x of 0 is equal to x of 0 plus x of 2 whereas x of 2 will be equal to x of 0 minus x of 2.
02:26
Then we have x of 4 is equal to x of 4 plus x of 6.
02:31
Then x of 6 will be equal to so it is x of 4 minus x of 6.
02:36
Then so here minus so the same term.
02:40
Then we have x of 1 is equal to x of 1 plus x of 3.
02:44
Then x of 3 will be equal to x of 1 minus x of 3.
02:48
X of 5 will be equal to x of 5 plus x of 7.
02:52
Similarly, we can write it for x of 7.
02:54
Now we have to consider for stage 3 that is for omega power 0, omega power 0 and omega power 0 we have x of 0 is equal to x of 0 plus x of 1.
03:06
Then x of 1 will be negative of this value.
03:10
X of 2 will be equal to x of 2 plus x of 3.
03:14
Then we have x of 3 is the negative term.
03:17
Then we have x of 4 is equal to x of 4 plus x of 5.
03:23
Then we can write for x of 5.
03:25
Again we have x of 6 is equal to x of 6 plus x of 7.
03:29
Write it for x of 7...