00:01
So here we have a square and it has been surrounded by a ring.
00:10
Ring having the radius is the r, square having the length l, and the solenoid is the 23 cm, having a radius 3 cm number of turns, 112 number of turns, and we have a very long solenoid of circular cross -sectional area.
00:32
And the square root having this length is the 1 .5 centimeters so the current in the solenoid is the 4 ampere so the flux so we know that flux equals to b times a and the current flowing through the solenoid so the magnetic field of the solenoid mu not n square y l times this area is the pi r so so this sorry, this for the solid and where it's mu not n i, so n by l times the pi r squared.
01:15
So this is the four pi square, 10 to the power minus 7.
01:19
This is 112 current is 4 now r squared.
01:25
So it's 9 into 10 to minus 4 over the length.
01:32
So it's 23, so 23 4.
01:35
So this will be 4 for the 16, 16 for the 64, 64, 64, 9, 7...