Question

The figure below shows a block with a mass of m = 6.30 kg that starts from rest at point A and slides on a track with negligible friction. Point A is at a height of h_a = 7.80 m. A m B C h_a 3.20 m 2.00 m (a) What is the block's speed at point B (in m/s)? m/s What is the block's speed at point C (in m/s)? m/s (b) What is the net work (in J) done by the gravitational force on the block as it moves from point A to point C?

          The figure below shows a block with a mass of m = 6.30 kg that starts from rest at point A and slides on a track with negligible friction. Point A is at a height of h_a = 7.80 m.
A m
B
C
h_a
3.20 m
2.00 m
(a) What is the block's speed at point B (in m/s)?
m/s
What is the block's speed at point C (in m/s)?
m/s
(b) What is the net work (in J) done by the gravitational force on the block as it moves from point A to point C?

Show more…

The figure below shows a block with a mass of m = 6.30 kg that starts from rest at point A and slides on a track with negligible friction. Point A is at a height of ha = 7.80 m.
A m
B
C
ha
3.20 m
2.00 m
(a) What is the block's speed at point B (in m/s)?
m/s
What is the block's speed at point C (in m/s)?
m/s
(b) What is the net work (in J) done by the gravitational force on the block as it moves from point A to point C?

Added by Seth H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

03/22/2022

Step 1

30 kg * 9.81 m/s^2 * 7.80 m = 486.342 J Final energy = mgh + 1/2 * mv^2 0 = 486.342 J + 1/2 * 6.30 kg * v^2 v = sqrt((2 * 486.342 J) / 6.30 kg) = 10.7 m/s Show more…

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The figure below shows a block with a mass of 6.30 kg that starts from rest at a point and slides on a track with negligible friction. The point has a height of 7.80 m. What is the block's speed at the point (in m/s)? What is the block's speed at point C (in m/s)? What is the net work (in J) done by the gravitational force on the block as it moves from point A to point C?

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