00:01
This problem, the first thing we're looking for is the electric field at a point two centimeters to the right of charge a, which is on the left here.
00:14
And i've written the actual charge values off to the side here.
00:19
Now, the electric field by definition is the force on unit positive charge, test charge.
00:26
It's imaginary.
00:27
You put it where you want the field, but it's not there.
00:30
But we use it as a device.
00:35
So we have to look at effectively the force of each other charges on it, and then we'll add those up, and they'll give us the net electric field.
00:42
So plus and plus is repulsion.
00:47
So the electric field contribution due to a is to the right, and plus x direction is to the right.
00:57
B, plus, plus, propulsion.
01:00
That will be to the left.
01:07
C is minus plus attractive.
01:13
So that is to the right.
01:16
So those are our three electric fields.
01:18
And we have to add up to get the net.
01:25
So e net x.
01:29
Now, ea is in the positive x direction.
01:33
So e .b is in the negative.
01:37
Eb.
01:38
So there's no angles involved.
01:40
So either it's plus or minus on the magnitude.
01:42
Plus ec.
01:46
And now we use the formula for the electric field of a point charge, k, magnitude of electric field, to be honest, to be precise...