00:01
The gaussian surface in the form of a cube of length is equal to 1 .9 meters and it is at a distance of x1 is equal to 5 .2 meters and y1 is equal to 3 .7 meters and the electric field is given as minus 3 .0 i cap minus 4 .4 y square j cap plus 2 .4 k cap newton per coulomb.
00:47
Now the charge that is enclosed in the cube has to be determined.
00:52
Now the net flux will be equal to the charge that is enclosed divided by epsilon naught.
01:04
So the net flux has to be determined to determine the charge that is enclosed.
01:09
The net flux in a cube can be given by the flux in the right side of the cube plus flux in the left side of the cube.
01:22
So considering the right side first, so flux on the right side will be equal to the flux is generally given by the electric field into area cos theta.
01:37
So the electric field here considering only the y component of the electric field into the area of the cube into cos, here the right side will be at an angle of 180 degrees.
01:51
So the component of electric field at y will be equal to modulus of 4 .4 y square into the area is the side square into cos 180 degree is minus 1.
02:08
Now the value of y in this cube the y distance is at an point of 4 .4 into y1 is given as 3 .7 meters the whole square into 1 .9 square minus 1.
02:27
So by calculating it we get the right flux as minus 2, 217 .45 newton meter square by coulomb...