Question

The figure shows a gear train. Gears have the following properties: N2 = 15 teeth N6 = 75 teeth N3 = 90 teeth N4 = 15 teeth Pd = 16 N5 = 75 teeth Pd = 12 N7 = 15 teeth Pd = 8 N8 = 60 teeth Determine the speed and direction of rotation of gear 8 when gear 2 drives to 3600 rpm clockwise. Determine the distance between centers of gears 2 and 8, as well as determine the ratio of angular velocity and mechanical advantage of the gear train.

          The figure shows a gear train. Gears have the following properties:
N2 = 15 teeth
N6 = 75 teeth
N3 = 90 teeth
N4 = 15 teeth
Pd = 16
N5 = 75 teeth
Pd = 12
N7 = 15 teeth
Pd = 8
N8 = 60 teeth
Determine the speed and direction of rotation of gear 8 when gear 2
drives to 3600 rpm clockwise. Determine the distance between centers
of gears 2 and 8, as well as determine the ratio of angular velocity and
mechanical advantage of the gear train.
        
Show more…
The figure shows a gear train. Gears have the following properties:
N2 = 15 teeth
N6 = 75 teeth
N3 = 90 teeth
N4 = 15 teeth
Pd = 16
N5 = 75 teeth
Pd = 12
N7 = 15 teeth
Pd = 8
N8 = 60 teeth
Determine the speed and direction of rotation of gear 8 when gear 2
drives to 3600 rpm clockwise. Determine the distance between centers
of gears 2 and 8, as well as determine the ratio of angular velocity and
mechanical advantage of the gear train.

Added by Sofia H.

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Figure 8 shows a single-stage gear train. Gear trains are used in many products, such as clocks and automotive transmissions, to reduce or increase the angular velocity of a component. The size of each gear is measured by the number of teeth rather than the radius. Suppose the first gear has $n_{1}$ teeth and the second gear has $n_{2}$ teeth. Because the spacing of the teeth is the same for both gears, the ratio of their radii will be equivalent to the corresponding ratio of the number of teeth. When two gears are meshed together, they share the same linear velocity. If $\omega_{1}$ and $\omega_{2}$ are the angular velocities of the first and second gears, respectively, then $$\begin{aligned}v_{2} &=v_{1} \\r_{2} \omega_{2} &=r_{1} \omega_{1} \\\omega_{2} &=\frac{r_{1}}{r_{2}} \omega_{1} \\\omega_{2} &=\frac{n_{1}}{n_{2}} \omega_{1} \end{aligned}.$$ The first gear in a single-stage gear train has 42 teeth and an angular velocity of 2 revolutions per second. The second gear has 7 teeth. Find the angular velocity of the second gear.

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Transcript

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00:01 Hello students, we have gears starting from 2 connecting to 3 with an internal gear 4 connected 4 is connected to 5 which is connected to 6 and having an internal gear 7 which is connected to 8 and we are given the given gear ratio so the rotational speed of gear 2 speed of 2 is equal to 3600 so we can find the speed ratio right speed ratio which is s2 by s8 will be equal to n2 by n8 this is the relation that we are going to use now he can clearly see these are all connected internally so in between there are a lot of connections from between s2 and s s s2 and s8 so we have to accommodate for all these things so you will get s2 by s8 will be equal to n2 connected to n3 divided by n4 divided by n5 divided by n6 divided by n7 divided by n8 this will be the internal connection that is how it is going to be so you can simplify this as n2 by n3 and then you can take that denominator to the top right so we can go from here so n2 by n3 will be equal to this will be equal to n8 will go to the top and this will comes to the top and bottom just like that so this is n4 and the bottom of that will remain there n5 times n6 by n7 times n8 this is how it is going to be looking…
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