00:02
Hi, here in this given problem, area of cross -section of the pipe is given as 64 centimeter square or we can say this is 64 into 10 to minus 4 meter square and area of cross -section of the throat in this venturi meter that is 32 centimeter square or we can say this is 32 into 10 x per minus 4 meter square.
00:32
Pressure in the pipe that is p1 is equal to 55 kioskal and gap in the level of water in the two manometer tubes that is given to be 1 .4 meter here so in the first part of the problem we have to find pressure difference at points 1 and 2 so that pressure difference between the points 1 and 2.
01:22
Delta p if we say simply that will be given by h row g.
01:30
This h that is the difference in the height, 1 .4 meter this is given as into density of the fresh water that is 1 ,000 meter cube and that is 1000 kilogram per meter cube into now 0 .8 pascal or it comes out to be equal to 137 kilo pascal the pressure difference here sorry this is 13 .7 kilo pascal which is the answer for the first part of the given problem here then in the second part of the problem we have to find the velocities of the water at the two points one and two for which first of all we will have to use an expression for the volumetric flow rate in the venturi meter and that expression is given as a 1 into a 2 square root of 2 g divided by a 1 square minus a 2 square square so, plugging in all the known values here, this is 64 into 32 into 10 dash far minus 4 each, so it will become 10 to minus 8, square root of 2 into 9 .8 into 1 .4 divided by square of 64 into 10 dash bar minus 4 minus square of 32 into 10 dash bar minus 4 again.
03:29
Then here it becomes 2048 into 10.
03:37
10 x4 minus 8.
03:39
Now taking this 10 x4 minus 4 as a common out of the square root, leaving behind 27 .44 in numerator and denominator will be 4 ,096 minus 1024...