00:01
Hi, here in this given problem this is the rough horizontal surface and a block kept over it initially at rest.
00:10
A force is being applied over the block like this at an angle theta, mass of the block m so its weight mg will be acting vertically down.
00:26
So normal reaction exerted by the surface on the block n that will be acting vertically up and that will be equal to mg using newton's third law of motion.
00:37
Now if we resolve this force in two components horizontal component f cos theta and vertical component f sin theta.
00:50
As the block is having a tendency to move towards right so there will be a force of friction towards left and as we have to find acceleration in the motion of the block means the block is moving so the friction will be kinetic friction.
01:07
Mass of the block m that is given as m only and force acting on it that is having a magnitude of 0 .500 times the weight of the block mg.
01:27
Angle theta that is 20 degree.
01:29
In the first part of the problem considering coefficient of kinetic friction mu k that is equal to 0 .510 normal reaction that will be given by weight mg acting vertically down minus component of the force vertical component of the force f sin theta...