00:01
Hello everyone, let's look at the given problem and in this problem we have been given four different loops and the current flowing through this is so i1 is given as 1 .8 ampere and the direction is outward and i2 is equal to 2 .8 ampere and this is the current going inward.
00:28
Similarly i3 is equal to 3 .8 ampere and this is the current going inward.
00:32
And it is coming outward and i4 is equal to 4 .4 ampere and this is going in load so for the sign convention here we will use the current coming outward will be taken as positive and the current going in watt we will consider this as negative now for loop a the current ia will be equal to so if you see the given loop a so this is loop a this section in which only i1 is the current flowing so this i a will be equal to i1 and this is coming outward that is the positive current so i a will be equal to 1 .8 period so this is the answer for the loop 1 current now in the second part we need to find the current in loop b so here we have loop b this one so this is this include the current i1 as well as i2 so i1 is outward and i2 is inward so we can write ib is equal to i1 i1 is 1 .8 ampere and i2 is 2 .8 amp so this will be minus 1 ampere so finally we can write ivy is minus 1 ampere so here negative sign shows that the current is inward so this is inward so this is the answer for the loop b.
02:11
Now, in the third part, that is for loop c, we need to find the current.
02:17
So again, if you see the loop c, that is this inward loop, it has only current i2.
02:22
So this will be equal to i2 and this current is going inward.
02:28
So we will write ic is equal to minus 2 .8 ampere.
02:33
Negative sign means the current is going inward.
02:36
So this is the answer for the loop c current...