The filament temperature of a light bulb is 2100 K when the bulb delivers 40.0 W of power. If its emissivity remains constant, what power is delivered when the filament temperature is 2500 K? A. 151 w B. 121 W C. 80.3 W D. 60.3 W
Added by Gregg C.
Step 1
We can rearrange this equation to solve for the power emitted at a different temperature: P2 = P1(T2/T1)^4 where P1 is the power emitted at the initial temperature T1, and P2 is the power emitted at the final temperature T2. Plugging in the given values, we Show more…
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A lamp having tungsten filament consumes $50 \mathrm{~W}$. Assume the temperature coefficient of resistance for tungsten is $4.5 \times 10^{-3}{ }^{\circ} \mathrm{C}^{-1}$ and temperature of the surrounding is $20^{\circ} \mathrm{C}$. When the lamp burns, the temperature of its filament becomes $2500^{\circ} \mathrm{C}$, then the power consumed at the moment switch is on, is (a) $608 \mathrm{~W}$ (b) $710 \mathrm{~W}$ (c) $215 \mathrm{~W}$ (d) $580 \mathrm{~W}$
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Round 2
The tungsten filament of bulb has resistance equal to $18 \Omega$ at $27^{\circ} \mathrm{C}$ temperature $0.25 \mathrm{~A}$ of current flows, when $45 \mathrm{~V}$ is connected to it If $\alpha=4.5 \times 10^{-3} \mathrm{~K}^{-1}$ for a tungsten then find the temperature of the filament. (A) $2160 \mathrm{~K}$ (B) $1800 \mathrm{~K}$ (C) $2070 \mathrm{~K}$ (D) $2300 \mathrm{~K}$
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