The first ionization energy, E, of a boron atom is 8.01×10^2 kJ/mol. What is the wavelength of light, in nanometers, that is just sufficient to ionize a boron atom? Refer to the values for constants. λ = nm
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Given: Ionization energy for one mole of boron = 8.01 x 10^2 kJ/mol Ionization energy for one boron atom = (8.01 x 10^2 kJ/mol) / Avogadro's number Ionization energy for one boron atom = (8.01 x 10^2 kJ/mol) / (6.023 x 10^23 atoms/mol) Ionization energy for one Show more…
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