The first-order reaction A ? B has a rate constant of 0.0643 s?¹. How many seconds will it take for 35.2% of A to react? Hint: 35.2 can be considered in a ratio to a starting original "amount" of 100 16.23 s -16.23 s 64.9 s 6.75 s 6.75 s?¹
Added by Jose Francisco C.
Close
Step 1
The half-life of a first-order reaction can be calculated using the formula: t1/2 = ln(2) / k, where t1/2 is the half-life and k is the rate constant. In this case, the rate constant is given as 0.0643 s^-1. So, t1/2 = ln(2) / 0.0643 = 10.77 s (approximately). Show more…
Show all steps
Your feedback will help us improve your experience
Madhur L and 73 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
If a reaction is first order with a rate constant of 0.0450 s-1, how much time is required for 55% of the initial quantity of reactant to be consumed?
Adi S.
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD